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What are the steps in solving 4/(x+1)-3/(x+2)=1?
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\[\frac{4}{x+1}-\frac{3}{x+2}=1\]\[\frac{4(x+2)-3(x+1)}{(x+1)(x+2)}\]
\[=1\]
\[\frac{4x+8-3x-3}{(x+1)(x+2)}=1\]
\[x+5=(x+1)(x+2)\]
\[x+5=x^2+3x+2\]\[x^2+2x-3=0\]
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\[(x+3)(x-1)=0\] x=-3 x=1
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