Question

Find an equation in general form for the straight line that passes thru the point (-1,4) and is perpendicular to the line 2x+3y=6

Answer 1

slope of 2x +3y =6 is -2/3
Line perpendicular to this line will have slope 3/2
y = 3/2 x + b
is the perpendicular line

This line passes through (-1,4)
Plug in x =-1 , y = 4 and solve for b
4 = 3/2(-1) +b
4 = -3/2 +b
4 +3/2 = b
11/2 =b

The line is y = 3/2x + 11/2
2y = 3x +11
2y -3x = 11 is the required line