Question

Find all solutions of the equation (x^2 -x-22)^(4/3)=16

Answer 1

Solve (x^2 -x-22)^(4/3)=16

16^(3/4) = (2^4) ^ (3/4) = 2^3 = 8
Equation (x^2 -x-22)^(4/3)=16 becomes
x^2 -x =8
x^2 -x -8 = 0
Solve it

Answer 2

Thank you