Question

solve this system of equation(cannot be a fraction)
x+y+z=1
2x+5y+2z=5
-x+6y-3z=-2
please show steps

Answer 1

r1:x+y+z=1
r2:2x+5y+2z=5
r3: -x+6y-3z=-2

(r2-2r1) 3y = 3
y=1

now substitute 1 for y in r1 and r3
r4:x+z=0
r5: -x -3z = -8

(r5+r4) -2z = -8
z=4

now substitute 4 for z in r4
x+4=0
x=-4