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I NEED HELP WITH find an equation for a line with slope -2/3 that contains point (6,-1)
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y=-(2/3)x+3
r u sure its correct how did you get that
y=-2/3x+b then you substitute -6,1 into the equation
since (-2/3) is the slope, it will go with x 6 is the x value, so plug that in for x and u get -4 -4+3=-1
@jahed: Check your other post.
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which one
is this one rightttt who is right amk11 or nykballa ????
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