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Mathematics 8 Online
OpenStudy (anonymous):

2x^3-4x^2-8x+3, find the minimum and maximum on interval [-2,1]...help

OpenStudy (anonymous):

Take the derivative. Set it equal to 0. Those are your critical points. If the derivative goes from positive to negative as it crosses a critical point then it is a max. If it goes from negative to positive it is a min.

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