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SOLVE: A. (x-3)^2=36 B. x^2-10x+25=64
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a. x - 3 = +-6 x = 9 or x = -3
(x-3)^2=36==> x=9 or x=-3 ,
(x-3)^2=36 x-3=sqrt(36) or x-3=-sqrt(36) x-3=6 or x-3=-6 x=6+3 or x=-6+3 x=9 or x=-3
(x-5)^2=64 ===> x=13 or x=-3
b. x -5)^2 = 64 x-5 = 8 or -8 x = 13 or -3
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the answer for a. is -3 and for b too
yes -3 is one of the roots in both equations
thank you jimmy :)
yw
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