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Mathematics 19 Online
OpenStudy (anonymous):

\[\sqrt[x]{8}=2\]

jimthompson5910 (jim_thompson5910):

\[\LARGE \sqrt[x]{8}=2\] \[\LARGE 8^{\frac{1}{x}}=2\] \[\LARGE (2^3)^{\frac{1}{x}}=2\] \[\LARGE 2^{\frac{3}{x}}=2\] \[\LARGE 2^{\frac{3}{x}}=2^1\] Since the bases are equal, the exponents are equal \[\LARGE \frac{3}{x}=1\] \[\LARGE 3=1*x\] \[\LARGE 3=x\] \[\LARGE x=3\] So the answer is \[\LARGE x=3\]

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