Question

FIND THE EQUATION FOR THE LINE THROUGH (2,5) AND (1,9)

Answer 1

y=-4x+13

Answer 2

m=(y2-y1)/(x2-x1)



m=(9-5)/(1-2)



m=(4)/(1-2)



m=(4)/(-1)



m=-4



So the slope of the line that goes through the points (2,5) and (1,9) is m=-4



Now let's use the point slope formula:



y-y1=m(x-x1)



y-5=-4(x-2)



y-5=-4x+-4(-2)



y-5=-4x+8



y=-4x+8+5



y=-4x+13



So the answer is y = -4x+13