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x^2+6x+8 factor.
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\[\Huge (x+2) (x+4) \]
\[ \Large (x+a)(x+b) = x^2+(a+b)\cdot x+ab \]
there is no a and there is no b....
he was just showing you how the factoring works
ab=8 and then a=2 and b=4
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okay so i just plug it in and get my answer?
actually, would the answer be x^2+8?
no, the left side of the relationship that YTM showed you is the factored form
the factored form of a second degree polynomial is, in general, the product of two linear binomials
okay
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saif gave the answer in the first post
okay, thats what i wrote on my paper... this algebra 2 stuff is really confusing me. hahah.
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