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Mathematics 7 Online
OpenStudy (anonymous):

x^2+6x+8 factor.

OpenStudy (saifoo.khan):

\[\Huge (x+2) (x+4) \]

OpenStudy (anonymous):

\[ \Large (x+a)(x+b) = x^2+(a+b)\cdot x+ab \]

OpenStudy (anonymous):

there is no a and there is no b....

OpenStudy (anonymous):

he was just showing you how the factoring works

OpenStudy (anonymous):

ab=8 and then a=2 and b=4

OpenStudy (anonymous):

okay so i just plug it in and get my answer?

OpenStudy (anonymous):

actually, would the answer be x^2+8?

OpenStudy (anonymous):

no, the left side of the relationship that YTM showed you is the factored form

OpenStudy (anonymous):

the factored form of a second degree polynomial is, in general, the product of two linear binomials

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

saif gave the answer in the first post

OpenStudy (anonymous):

okay, thats what i wrote on my paper... this algebra 2 stuff is really confusing me. hahah.

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