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1/4^-3
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4^3 \[4 \times 4 \times 4\] = answer
\[\frac{1}{4^{-3}}\] \[\frac{1}{4*4*4}\] \[\frac{1}{64}\]
(1/4)^-3 (4^-1)^-3 4^(-1*-3) 4^3 64
Not sure if blue 12 use the correct process but the solution is correct.
blue 12 is right
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ok I looked at it again. Not sure I would have done it that way. I would have taken your approach. I try to do things (Keep it simple-Approach)
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