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Find the equation of the line through the points (1,7) and (3, -1).
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y = -4x + 11
Can you explain your work? I got something different.
\[\underline{Slope}\]\[=\large{\frac{y_2-y_1}{x_2-x_1}}\]
\[= \frac{-1-7}{3-1} = \frac{-8}{2}=-4\]
m = -1-7/3-1 = -4 y = mx + b 7 = -4(1) + b 7 = - 4 + b b = 11 y = -4x + 11
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now \[y-y_1=m(x-x_1)\]\[y-7=-4(x-1)\]
\[y-7=-4x+4\]\[y=-4x+11\]
Thank you both!
\[\Huge{{your}} \Huge{\underline{Welcome}}\]
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