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prove that 2 = 1?
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lalaly!!! your back!! :-)))
lols, i saw this once let a=b multiply by a a^2=ab add a^2 2a^2=ab+a^2 subtract 2ab 2a^2-2ab=a^2-ab 2(a^2-ab)=a^2-ab divide by a^2-ab 2=1
a = b a^2 = a*b a^2-b^2 = a*b-b^2 (a+b)(a-b) = b(a-b) (a+b) = b a+a = a 2a = a 2 = 1
hahahaha!! LOL!!!
This is wrong because you are dividing by 0
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0?
(a+b)(a-b) = b(a-b) a-b=0 (a+b) 0= b 0
yes remember that a = b so a-b = 0 which is undefined
lol haha ok
so it is more like prove of 0=0
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