Question

find the x intercept of the parabola y=-3x^2+11x+3 using the quadratic formula?

Answer 1

\[0=-3x^2+11x+3\]
\[x=\frac{-11 \pm \sqrt{11^2-4(-3)(3)}}{2(-3)}\]

Answer 2

Right but the -6
my calculator won't give me an answer

Answer 3

?

Answer 4

if you solved that you'd end up with -11+sqroot157/-6

Answer 5

when you plug it into a calculator it says it cannot give me answer because it thinks that its a negative under the sqroot

Answer 6

yes thats right don't forget -6 goes underneath the -11 too
and also you have the other solution with - and between the two terms in the numerator

Answer 7

ah okay