Question

solve for x
6x+2=x^2 +16x+18

Answer 1

\[x ^{2}+10x+16\]

Answer 2

Right,
x^2 + 10x + 16 = 0.

Now, you should be able to see by inspection what are the factors. But if not, use the quadratic formula.

Answer 3

x_1,_2=(-16+/- sqrt(100-72))/2

Answer 4

(x+8)(x+ 2)= 0

Answer 5

Alboltz if you have trouble with factoring this may help
x^2+10x+16=0
(x+a)(x+b)=0
you need to find a and b
such that x^2+(a+b)x+(ab)=0
your coefficient in front of the x tern is 10
the coefficient in the last tern is 16
A+B=10
AB=16
now just find two numbers that satisfy both those equations
(x+8)(x+2)=0
so your x's which satisfy this are x=-8 x=-2

Answer 6

x^2+10x+16=0
(x+8)(x+2)
x=-8, x=-2