Question

Find the general form of the equation of the the circle.

Center at the point (-4, -3); containing the point (-3, 3

Answer 1

equation of circle
\[(x-(-4))^2+(y-(-3))^2=r^2\]\[(x+4)^2+(y+3)^2=r^2\]

Answer 2

tofind r
substitute (-3,3) in x and y

Answer 3

\[(-3+4)^2+(3+3)^2= 1+36=37\]
so 37=r^2