An outfielder throws a baseball with an initial speed of 35m/s at an angle of 29degrees to the horizontal. The ball leaves his hand from a height of 1.90m. How long is the ball in the air before it hits the ground?

Question

anonymous · Answer

initial speed of 35m/s at an angle of 29degrees to the horizontal

 a height of 1.90m

you will write velocity in x and y component

anonymous · Answer

is it the equation Vox + axt and Vy=Voy-9.8t

anonymous · Answer

$$Height=H_0+ V_y t- 1/2(a) t^2$$
$$Height=1.90+ 35 sin(35)t- 1/2(9.8) t^2$$

anonymous · Answer

correction

$$Height=1.90+ 35 sin(29)t- 1/2(9.8) t^2$$

anonymous · Answer

Solve for  t

$$0=1.90+ 35 sin(29)t- 1/2(9.8) t^2$$

anonymous · Answer

did you get 3.57 as the answer?

anonymous · Answer

yes

anonymous · Answer

thank you so much

anonymous · Answer

Good job