Question

what is the value of x, y, and z for (5/4)x-(4/3)y+(5/4)z=6 , (5/16)x+(5/4)y-(4/16)z=-4 , (3/4)x-1y+(3/4)z=6

Answer 1

\[(5/4)x-(4/3)y+(5/4)z=6 \times12\]
\[15x -16y+15z=72\]

\[(5/16)x+(5/4)y-(4/16)z=-4 \times 16\]
\[5x+20y-4z=-64\]

\[(3/4)x -y+(3/4)z=6 \times 4\]
[3x-4y+3z=24

after that you can using subtitute or eliminate in order to get the value of x, y, z