Question

find dy/dx of x^y = y^x

Answer 1

\[ y^\prime = -{\frac {y \left( -{x}^{y}y+{y}^{x}x\ln \left( y \right) \right) }{x
\left( {y}^{x}x-\ln \left( x \right) y{x}^{y} \right) }} \]
Use implicit differentiation