Question

how do I do this question 2/x-3 >_2
please help me on thisthanks :D

Answer 1

is that (2/x) - 3, or 2/(x-3)? and is that -2?

Answer 2

no is an greater equal sign

Answer 3

and my other question?

Answer 4

nop is 2 divided by x-3

Answer 5

\[\frac{2}{x-3} \ge 2\] \[2 \ge 2x - 6\] \[8 \ge 2x\] \[4 \ge x\]

Answer 6

hey there how did u do that
?

Answer 7

multiplied both sides by x-3 and solved. Notice the solution is only valid for \[3 \lt x \le 4\] because at x=3 the equation is undefined, and at x < 3, the solution is negative.

Answer 8

the graph: http://bit.ly/pauLUV

Answer 9

omq thanks so much :)

Answer 10

hey the solution I have to give in interval notation so how do u think I should do it?

Answer 11

(3,4]

Answer 12

yeah Thats what I got :)

Answer 13

thankss

Answer 14

hey did you know how to solve (5-3/x)/(1+4/x^2)