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Determine # of solutions: 1/3x2- 5x +25
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From (1/3)x^2-5x+25, we see that a = 1/3, b = -5 and c = 25 D=b^2-4ac D=(-5)^2-4(1/3)(25) D=25-4(1/3)(25) D=25-100/3 D=-25/3 So the discriminant is D=-25/3 Since the discriminant is less than zero, this means that there are two complex solutions. In other words, there are no real solutions.
So the formula to find a discriminant is b^2-4ac?
yep, that's it
Thanks so much!
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