Question

Hey lalaly, I have one more: Factor the expression 16a^2-72ab+81b^2 into a product of binomials. Can you help me with this type of equation please?:)

Answer 1

(4a-9b)^2

(a-b)^2=a^2-2ab+b^2

Answer 2

\[a^2-2ab+b^2= (a-b)(a-b)\]
\[16a^2-72ab+81b^2= (4a-9b)(4a-9b)\]

Answer 3

notice that
\[\large{16a^2-72ab+81b^2}= (4a)^2-(2 \times 4 \times 9)ab+ (9b)^2\]

Answer 4

so it would be (4a-9b)^2 = (4a-9b)(4a-9b), am I right?

Answer 5

yess thats right:D

Answer 6

oh you got this:) great studying

Answer 7

;):D

Answer 8

;-)