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OpenStudy (anonymous):
integrate 1/(4-x^2)
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OpenStudy (anonymous):
1/(4-x^2) = (1/4) [(1/x+2)-(1/x-2)] On integrating this we get 1/(4-x^2) =Ln ( l x+2 l / l x-2 l )
OpenStudy (anonymous):
kk thanks :)
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