Question

A particle is moving along a projectile path where the initial height is 160 feet with an initial speed of 144 feet per second. What is the maximum height of the particle?

128 feet

224 feet

272 feet

484 feet

Answer 1

Use the formula:
\[v^2=u^2+2as\]solving for s. (v is the velocity at the maximum height [which must be 0], u is the initial velocity [144f/s], a is the acceleration due to gravity [I don't know what this is in imperial units, it's probably in your textbook], and s is the displacement the particle goes through during this movement [remember that you have to add 160 feet to this value])

Good luck!