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how do I evaluate 2^3 / 2^0 - 2^-1?
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7 1/2? cause 8 divided by 1 is 8 subtracted from 1/2 which is 2^-1?
(8/1) -(1/2) = 15/2
steps please :(
2 to the 3rd power is 8, and 2^0 is 1 and 2^-1 is 1/2
\[(2{}^{\wedge}3/2{}^{\wedge}0)-(2{}^{\wedge}-1) \]\[(8)-\left(\frac{1}{2}\right) \]\[\frac{15}{2} \]
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