Two investments were made totalling $50,000. One investment at 8 1/2% and the other at 6%. If the total earned income was $3500, how much was the investment?

Question

anonymous · Answer

please answer it, please

anonymous · Answer

lets put amount invested at 81/2% as x and the rest will therefore be 50,000-x
the solve 
$$.085x=.06(50,000-x)=3500$$ to get your answer

gw2011 · Answer

Let x=Investment at 8 1/2%
Let y=Investment at 6%

0.085x+0.06y=3000
x+y=3500                     Multiply this equation by 0.06 to eliminate y and find x

0.085x+0.06y=3500
0.06x+0.06y=3000  Subtract this equation from the above

0.025x=500
x=$20,000  This is the investment at 8 1/2%
y=$30,000  This isthe investment at 6%