Find an equation for the line satisfying the given conditions. Through (3, 4) and parallel to 5x - 3y = 9.
y=(5/3)x-1
(3,4) is a coordinate where x = 3 and y = 4. If the line you are looking for needs to be parallel to 5x-3y = 9, this means that it needs to have the same slope. Your first step is to get the equation given to you into y=mx+b form. 5x - 3y = 9 -3y = -5x + 9 y = (5/3)x - 3 Your slope (m) is 5/3. This needs to be the slope in your new equation. Also, if the line you are looking for passes through the point (3,4) , this means you can plug in these numbers as your x and y so you can solve for "b". y = mx + b 4 = (5/3)(3) + b 4 = 5 + b -1 = b. Now you can plug the "m" and "b" that you have found into your y = mx + b equation. y = (5/3)x -1
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