Reginald was driving a boat at 60mph against the current for 2 hours. Reginald took the same trip with the current it took a 1 hour and 15 minutes. Calculate how fast Reginald was traveling in the water with the current.

Question

anonymous · Answer

$$v_xt_x=s$$s is constant, so we can say:$$v_1t_1=v_2t_2$$
$v_1$ is the velocity against the current (60mph - current velocity), $t_1$ is the time taken to travel the displacement s at that velocity.
$v_2$ is the velocity with the current (60mph + current velocity), $t_2$ is the time taken to travel the displacement s at that velocity.

So:$$(60-c)(2) = (60+c)(1.25)$$Solve for c!