Question

solve by completing the square x^2-8x+32=0

Answer 1

use x^2-2xy+y^2=(x+y)^2, now just find out what is y in this !

Answer 2

(x-Y)^2 i meant :D

Answer 3

(x-4)^2 - 16 + 32 = 0
(x-4)^2 = -16
take sqrt both sides

Answer 4

ok but when i get 4+or-4i how do I determine if it is just +4i or if it is +or- 4i

Answer 5

x-4 = 4i or - 4i
x = 4 + 4i
or 4- 4i

done