Question

Simplify 6{[3(a-4)+17]-[3(2a-2)+5]}

Answer 1

\[36-18a\]

Answer 2

This is what I got:

6{3(a-4) + 17] - [3(2a - 2) + 5]}

= 6(3a - 12 + 17 - 6a - 6 + 5)

= 6(3a + 5 - 6a - 1)

= 6(-3a + 4)

= -18a + 24

Answer 3

6{[3(a-4)+17]-[3(2a-2)+5]}

=6(3a-12+17-6a-6+5)

=6(3a+5-6a-1)

6(8a-5a)

=3a

Answer 4

How did you get down to 3a? How did you remove the non-variables?