Question

let f(x,y)= x^2cos(piy)-ln(2xy) find fx(2,3)+ fy(2,3)

Answer 1

\[x^2 cos(\pi y)- ln(2xy)\]

\[f_x= 2x cos(\pi y)-\frac{2y}{2 x y}\]

\[f_x= 2x cos(\pi y)-\frac{1}{ x }\]

Answer 2

\[f_y=-x^2\pi sin(\pi y)-\frac{1}{y} )\]

Answer 3

\[f_x(2,3)=2(2)cos(\pi 3)- \frac{1}{2}\]

Answer 4

i got -29/6
thanks so much

Answer 5

enjoying calc 3?

Answer 6

hahahah....fun stuff...enjoying tutoring?

Answer 7

not really, not enough hours

Answer 8

:( is it a parttime job?
can u help me with another problem?

Answer 9

post it, I will come back in about half an hour

Answer 10

k thanks :)