Question

How do you factor out 1 + 27y^3?

Answer 1

a³ + b³=( a + b )( a² – ab + b² )
1^3+(3y)^3=(1+3y)(1^2-1*3y+(3y)^2)=
(1+3y)(1-3y+9y^2))

Answer 2

Thank you so much.

Answer 3

You are welcome, Here is the full list
[1] ( a + b )² = a² + 2ab + b² ,
[2] ( a – b )² = a² – 2ab + b² ,
[3] ( a + b ) ( a – b ) = a² – b²,
[4] ( a + b )³ = a³ + 3a² b + 3ab² + b³ ,
[5] ( a – b )³ = a ³ – 3a² b + 3ab² – b³ ,
[6] ( a + b )( a² – ab + b² ) = a³ + b³ ,
[7] ( a – b )( a ² + ab + b² ) = a³ – b³ .