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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
I need help with a problem. Ive been trying to figure it out but i am lost
OpenStudy (anonymous):
k hit me with ur best shot but not to hard k
OpenStudy (anonymous):
a contractor must triangulate 3 common areas in a subdivision which must be 2/3 the distance from the community center. The community center is 1/3 the distance from all emergency center.
ML=16 LP=10 OQ= 21
OpenStudy (anonymous):
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OpenStudy (anonymous):
what is ML and that things at the bottom for
OpenStudy (anonymous):
what does it want you to do
OpenStudy (anonymous):
I have no idea thats how my instructor had it on the board. He said to basically find all distances.
OpenStudy (anonymous):
what do u need to find out the length
OpenStudy (anonymous):
I need to find out the distance. I believe the median of each line segment
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OpenStudy (anonymous):
in what cm in degrees
OpenStudy (anonymous):
Its confusing me. I guess it wants you to find 2/3 of line segments ml , lp, oq and 1/3 from all distances
OpenStudy (anonymous):
well it is not degrees cm or inch i don't know what he/she wants u to do
OpenStudy (anonymous):
Thats okay, thanks.
OpenStudy (anonymous):
i think i know how to do it though
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