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Mathematics 20 Online
OpenStudy (anonymous):

Anyone good in geometry?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

I need help with a problem. Ive been trying to figure it out but i am lost

OpenStudy (anonymous):

k hit me with ur best shot but not to hard k

OpenStudy (anonymous):

a contractor must triangulate 3 common areas in a subdivision which must be 2/3 the distance from the community center. The community center is 1/3 the distance from all emergency center. ML=16 LP=10 OQ= 21

OpenStudy (anonymous):

OpenStudy (anonymous):

what is ML and that things at the bottom for

OpenStudy (anonymous):

what does it want you to do

OpenStudy (anonymous):

I have no idea thats how my instructor had it on the board. He said to basically find all distances.

OpenStudy (anonymous):

what do u need to find out the length

OpenStudy (anonymous):

I need to find out the distance. I believe the median of each line segment

OpenStudy (anonymous):

in what cm in degrees

OpenStudy (anonymous):

Its confusing me. I guess it wants you to find 2/3 of line segments ml , lp, oq and 1/3 from all distances

OpenStudy (anonymous):

well it is not degrees cm or inch i don't know what he/she wants u to do

OpenStudy (anonymous):

Thats okay, thanks.

OpenStudy (anonymous):

i think i know how to do it though

OpenStudy (anonymous):

Give it a shot.

OpenStudy (anonymous):

k

OpenStudy (anonymous):

nr is 16

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