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OpenStudy (anonymous):
Inverse trigonometric functions(Calculus) u=Arctan x/a ans: du/dx=a/a^2+x^2 u= Arcsin x/a, a>0ans: du/dx= 1/sq. root a^2-x^2
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OpenStudy (anonymous):
pls. explain how come the answer became like that.
OpenStudy (anonymous):
is the question how to derive such a thing?
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