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Mathematics 10 Online
OpenStudy (anonymous):

Prove that: cosx(tanx+cotx)=cscx

OpenStudy (anonymous):

\[LHS=cosx(\frac{sinx}{cosx}+\frac{cosx}{sinx})=cosx(\frac{\sin^2x+\cos^2x}{sinxcosx})\] \[=cosx(\frac{1}{sinxcosx})\] \[=\cancel{cosx}(\frac{1}{sinx \cancel{cosx}})\] \[=\frac{1}{sinx}=cosecx=RHS\]

OpenStudy (anonymous):

awesome!

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