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The doorsill of a campus building is h = 7 feet above ground level. To allow wheelchair access, the steps in front of the door are to be replaced by a straight ramp with constant slope 1/10, as shown in the figure. How long must the ramp be? [The answer is not 70 feet.]
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a^2 + b^2 = c^2 7^2 + 70^2 = c^2 49 + 4900 = c^2 4949 = c^2 c^2 = 4949 c = sqrt(4949) c = 70.349129 So the ramp is approximately 70.349129 ft
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