Question

the sum of numberand its reciprocal is 73/24. find the number?

Answer 1

let the number be x.

so,

\[x+{1\over{x}}={73\over24}\]

Answer 2

\[{x^2+1\over{x}}={73\over24}\]

Answer 3

\[24x^2-73x+24=0\]
\[\left( x-{8\over3} \right)\left( x-{3\over8} \right)=0\]
\[x={8\over3},{3\over8}\]

so just choose either answer (: