Question

find two numbers whose sum is 28 and whose product is 96.

Answer 1

let the 2 numbers be x and y.

x+y = 28
xy = 96

Answer 2

x = 28 - y

So, y(28-y) = 96
28y-y^2 = 96
y^2 - 28y +96 = 0
(y-24)(y-4)=0
y=4,24
When y = 4, x = 24
When y = 24, x = 4

So the 2 numbers are 4 and 24.