Question

anjo works 5 mins. faster than aira in cleaning the room. if they work together, they can finish the job in 6 mins. How long can each of them clean the room working alone?

Answer 1

\[\Large \frac{1}{x}+\frac{1}{x+5}=\frac16\]Solve for x.

Answer 2

then ?

Answer 3

then, take the LCM and solve.

Answer 4

whats the next steps ? please ???

Answer 5

pls

Answer 6

let anjo can finish in x min
so aira can finish in x+5 min

in 1 min anjo can do 1/x part of work

in 1 min aira can do 1/(x+5) part of work

togather in 1 min they can do 1/x + 1/(x+5) part of work

they finished togather in 6 min

so 6[1/x + 1/(x+5)] = 1

(6/x)+(6/(x+5))=1

6(x+5)+6(x)=(x)(x+5)

6x+30+6x=x^2+5x

x^2-7x-30=0

(x-10)(x+3)=0

x=-3 and x=10

time cannot be negative

so x=10

x+5= 10+5=15