The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?

Write the system of equations that would be used to solve this problem.

Question

The perimeter of a rectangle is 56 inches. The length is 4 more than 3 times the width. What are the dimensions of the rectangle?

Write the system of equations that would be used to solve this problem.

anonymous · Answer

x = 3y+4

x = lenght
y = width

2(3y+4) + 2y = 56

8y = 48

y = 6

x = 22

anonymous · Answer

i dont understand here are my options 

L+W=56
L=3W+4



L+W=56
W+4=3L

2L+2W=56
W=3L+4


2L+2W=56
L=3W+4

anonymous · Answer

A (L+W=56 
L=3W+4 )

B (L+W=56
 W+4=3L)
 
C (2L+2W=56 
W=3L+4)
 
D (2L+2W=56
 L=3W+4)

anonymous · Answer

D.