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anti derivative of ((x - 1)^2) / x^2
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Note first that ((x - 1)^2) / x^2 = ( x^2 - 2x + 1 ) / x^2 = 1 - 2/x + 1/x^2 Can you integrate it now?
=( x^2 - 2x + 1 )/ x^2 = 1 - 2/x + 1/x^2 integrate these one by one
yes thank you, I did the first step wrong!
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