Question

t^2+10t+26=0

quadratic formula

Answer 1

\[(t-5)^2+1\]

Answer 2

x = 5 + sqrt(-1)
x = 5 - sqrt(-1)

Answer 3

Quadratic formula=[-b+/-square root(b^2-4ac)]/2a

a=1
b=10
c=26

[-10+/-square root (10^2-4(1)(26)]/2(1)
[-10+/-square root(100-104)]/2
[-10+/-square root-4]/2
[-10+/-square root(-1)(4)]/2
[-10+/-2 square root -(1)]/2
[-5+/-square root (-1)]/2 The square root of -1=i
-5+/-i