Question

-Under the Quadratic equation (ROOTS)
Find the dimensions of a rectangle whose length is 5 less than twice its width and whose area is 63 square units.

Answer 1

let width be w
then the lenght = 2w - 5

area = l*w
63 = w(2w-5)

2w^2 - 5w - 63 = 0

2w^2 -14 w + 9w - 63 = 0

(2w+9)(w-7)=0

so width = 7

then length = 9