Question

y varies jointly with p and q. When p = 12 and q = 4, y = 144. Find y when p = 10 and q = 6.

Answer 1

y = kpq
144 = k(12)(4)

k = 3

y = 3(10)(6)

y = 180

:)

Answer 2

Thank you, again :) lol

Answer 3

your welcome :))

Answer 4

Calculate the constant k
y=kpq
144=(12)(4) k
k=3
y=(3)(10)(6)=180

Answer 5

very good kumarsajan, the step by step really helps the student.

Answer 6

thank you radar.
:))

Answer 7

Agreed.