Question

What are the solution intervals for |2x + 7| – 3 > 2?

Answer 1

x > -1
x > -6

Answer 2

first just do the equation:

2x + 7 -3 > 2
x >-1

then change the sign of the numbers inside the absulute symbol;

-2x - 7 - 3 > 2

x > -6

Answer 3

no thats a wrong answer

| 2x - 7| > 1

for |x|>a x<-a x>a

so

2x-7< -1

2x<6

x<3

2x - 7>1

2x > 8

x>4

so x belongs to (- infinite , 3) union (4 , infinite)