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OpenStudy (anonymous):
What is the solution set for |x – 2|– 1 > 2?
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jimthompson5910 (jim_thompson5910):
|x – 2|– 1 > 2 |x – 2| > 2 + 1 |x – 2| > 3 x – 2 > 3 or x - 2 < -3 x > 3 + 2 or x < -3 + 2 x > 5 or x < -1
OpenStudy (anonymous):
|x – 2|– 1 > 2 ===> |x – 2| > 3 ===>x-2 > 2 ==> x>4 or x-2<-2 ==> x<0
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