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Mathematics 16 Online
OpenStudy (anonymous):

solve l2x+7l<3

OpenStudy (anonymous):

the answer is x<-2 or x>-5

OpenStudy (anonymous):

the question is more like this- l2x+7l<1 is equivalent to which of the following? a) x<-3 b) x <3 c) 3<x<4 d) -4<x<-3 e) 0<x<3

OpenStudy (anonymous):

ohh...srry i dunno...

OpenStudy (anonymous):

how did u solve the first one??

OpenStudy (anonymous):

i mean like what does the line have to do with the equation

OpenStudy (anonymous):

well since it is a an abosulute value it can be negative or postitive, okay her is the first one l2x+7l<3 2x+7<3 solve that which is equal to x<-2 then you gotta do the negative way too -2x+7<3 divide by -1 2x+7>-3 (when dividing by a negative, always switch signs then you get x>-5 i think thats how u do it or what u meant...

OpenStudy (anonymous):

u always come up wit two answers for absoulute value equations

OpenStudy (anonymous):

thanks mate :) that helped

OpenStudy (anonymous):

sure anytime!!

OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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