Question

2ln(x+1)-1=0. Solve for x.

Answer 1

\[\ln (x+1)=1/2\]So,\[x+1=\sqrt{e}\]and,\[x=\sqrt{e}-1\]

Answer 2

2ln(x+1)-1=0 ===>ln(x+1)=1/2 ===> \[\sqrt{e}=x+1\]

Answer 3

==>\[ x=\sqrt{e} -1\]