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A long distance trucker traveled 160 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 4 hours less gime. The going speed was ?? mph.
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20 mph
lets see why. time is \[\text {time}=\frac{\text{distance}}{\text{rate}}\] the distance both directions is 160. if the rate going it r, then the rate returning is 2r (double) and you are told that the time returning is 4 hours less than the time going. so an equation could be \[\frac{160}{r}=\frac{160}{2r}+4\]
solve this for r to get 20 and the check is easy. going took \[\frac{160}{20}=8\] and \[\frac{160}{40}=4\]
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