Question

find xintercepts and vertex of the porabola y=x^2+10x+25

Answer 1

y=(x+5)^2 ===> vertex = (-5,0) , x-itercept is x=-5

Answer 2

-5 is root and (-5,0) is the vertex.
http://www.wolframalpha.com/input/?i=+y%3Dx^2%2B10x%2B25+vertex

Answer 3

find the xintercepts and vertext of the porabola y=x^2+2x-24

Answer 4

y = (x + 1)^2+ -25
no x-intercept since vertex is at (-1,-25)
http://www.wolframalpha.com/input/?i=y+%3D++%28x+%2B+1%29^2%2B+-25+vertex